s = '{foo} {bar}'
s.format(foo='FOO', bar='{bar}')
from: https://stackoverflow.com/questions/11283961/partial-string-formatting
s = '{foo} {bar}'
s.format(foo='FOO', bar='{bar}')
from: https://stackoverflow.com/questions/11283961/partial-string-formatting
In Python 3, you can use dict.items()
to get a set-like view of the dict items. You can then use the <=
operator to test if one view is a "subset" of the other:
d1.items() <= d2.items()
In Python 2.7, use the dict.viewitems()
to do the same:
d1.viewitems() <= d2.viewitems()
In Python 2.6 and below you will need a different solution, such as using all()
:
all(key in d2 and d2[key] == d1[key] for key in d1)
from: https://stackoverflow.com/questions/9323749/how-to-check-if-one-dictionary-is-a-subset-of-another-larger-dictionary
# Import the JSON module
from: https://linuxhint.com/sort-json-objects-python/
int(value or 0)
from: https://stackoverflow.com/questions/3930188/how-to-convert-nonetype-to-int-or-string
all you will need to do is
klass = globals()["class_name"]
instance = klass()
from: https://stackoverflow.com/questions/3451779/how-to-dynamically-create-an-instance-of-a-class-in-python
You can assign an iterable to side_effect
, and the mock will return the next value in the sequence each time it is called:
>>> from unittest.mock import Mock
>>> m = Mock()
>>> m.side_effect = ['foo', 'bar', 'baz']
>>> m()
'foo'
>>> m()
'bar'
>>> m()
'baz'
from: https://www.py4u.net/discuss/16628
I prefer to do this in one line of code.
my_dict = {} my_dict[some_key] = my_dict.get(some_key, 0) + 1
from: https://stackoverflow.com/questions/473099/check-if-a-given-key-already-exists-in-a-dictionary-and-increment-it