This is working for linux and windows as well with standard library
paths = ['a/b/c/', 'a/b/c', '\\a\\b\\c', '\\a\\b\\c\\', 'a\\b\\c',
'a/b/../../a/b/c/', 'a/b/../../a/b/c']
def path_leaf(path):
return path.strip('/').strip('\\').split('/')[-1].split('\\')[-1]
[path_leaf(path) for path in paths]
from: https://stackoverflow.com/questions/8384737/extract-file-name-from-path-no-matter-what-the-os-path-format
